%
%	GenEduQ0001
%
%	Seed = -1 (-1488580597)
%

\Ques{1}{\[
\frac{
1^2+3^2+5^2+7^2
}{
(64-1)^2+(49-4)^2+(36-9)^2+(25-16)^2
}
\]}{\[
\frac{
1
}{
81
}
\]}{\begin{eqnarray*}
\mbox{Ϳ��}
&=&
\frac{
1^2+3^2+5^2+7^2
}{
(64-1)^2+(49-4)^2+(36-9)^2+(25-16)^2
}
\\
&=&
\frac{
1^2+3^2+5^2+7^2
}{
(8^2-1^2)^2+(7^2-2^2)^2+(6^2-3^2)^2+(5^2-4^2)^2
}
\\
&=&
\frac{
1^2+3^2+5^2+7^2
}{
((8+1)(8-1))^2+((7+2)(7-2))^2+((6+3)(6-3))^2+((5+4)(5-4))^2
}
\\
&=&
\frac{
1^2+3^2+5^2+7^2
}{
(9\times7)^2+(9\times5)^2+(9\times3)^2+(9\times1)^2
}
\\
&=&
\frac{
1^2+3^2+5^2+7^2
}{
9^2(7^2+5^2+3^2+1^2)
}
\\
&=&
\frac{
1^2+3^2+5^2+7^2
}{
9^2(1^2+3^2+5^2+7^2)
}
\\
&=&
\frac{
1
}{
81
}
\end{eqnarray*}}
